#### Electronics :: All Aptitude Test ::

 1. Convert (214)8 into decimal? A. (140)10 B. (141)10 C. (142)10 D. (140)10

 2. Convert (0.345)10 into an octal number? A. (0.16050)8 B. (0.26050)8 C. (0.19450)8 D. (0.16050)8

 3. Convert the binary number (01011.1011)2 into decimal? A. (11.6875)10 B. (11.5874)10 C. (10.9876)10 D. (11.6875)10

 4. Octal to binary conversion: (24)8 =? A. (111101)2 B. (010100)2 C. (111100)2 D. (111101)2

 5. Convert binary to octal: (110110001010)2 =? A. (5512)8 B. (6612)8 C. (4532)8 D. (5512)8

 6. What is the addition of the binary numbers 11011011010 and 010100101? A. 0111001000 B. 1100110110 C. 11101111111 D. 0111001000

 7. Perform binary addition: 101101 + 011011 = ? A. 011010 B. 1010100 C. 101110 D. 011010

 8. Perform binary subtraction: 101111 – 010101 = ? A. 100100 B. 010101 C. 011010 D. 100100

 9. Binary subtraction of 100101 – 011110 is? A. 000111 B. 111000 C. 010101 D. 000111

 10. Perform multiplication of the binary numbers: 01001 × 01011 = ? A. 001100011 B. 110011100 C. 010100110 D. 001100011

 11. 100101 × 0110 = ? A. 1011001111 B. 0100110011 C. 101111110 D. 1011001111

 12. On multiplication of (10.10) and (01.01), we get? A. 101.0010 B. 0010.101 C. 011.0010 D. 101.0010

 13. Divide the binary numbers: 111101 ÷ 1001 and find the remainder? A. 0010 B. 1010 C. 1100 D. 0010

 14. Divide the binary number (011010000) by (0101) and find the quotient? A. 100011 B. 101001 C. 110010 D. 100011

 15. Binary subtraction of 101101 – 001011 = ? A. 100010 B. 010110 C. 110101 D. 100010

 16. 1’s complement of 1011101 is? A. 0101110 B. 1001101 C. 0100010 D. 0101110

 17. 2’s complement of 11001011 is? A. 01010111 B. 11010100 C. 00110101 D. 01010111

 18. On subtracting (01010)2 from (11110)2 using 1’s complement, we get? A. 01001 B. 11010 C. 10101 D. 01001

 19. On subtracting (010110)2 from (1011001)2 using 2’s complement, we get? A. 0111001 B. 1100101 C. 0110110 D. 0111001

 20. On subtracting (001100)2 from (101001)2 using 2’s complement, we get? A. 1101100 B. 011101 C. 11010101 D. 1101100

 21. On addition of 28 and 18 using 2’s complement, we get ? A. 00101110 B. 0101110 C. 00101111 D. 00101110

 22. On addition of +38 and -20 using 2’s complement, we get? A. 11110001 B. 100001110 C. 010010 D. 11110001

 23. On addition of -46 and +28 using 2’s complement, we get? A. -10010 B. -00101 C. 01011 D. -10010

 24. On addition of -33 and -40 using 2’s complement, we get? A. 1001110 B. -110101 C. 0110001 D. 1001110

 25. On subtracting +28 from +29 using 2’s complement, we get? A. 11111010 B. 111111001 C. 100001 D. 11111010

 26. If the number of bits in the sum exceeds the number of bits in each added numbers, it results in? A. Successor B. Overflow C. Underflow D. Successor

 27. An overflow is a? A. Hardware problem B. Software problem C. User input problem D. Hardware problem

 28. An overflow occurs in? A. MSD position B. LSD position C. Middle position D. MSD position

 29. Logic circuitry is used to detect? A. Underflow B. MSD C. Overflow D. Underflow

 30. 1’s complement can be easily obtained by using? A. Comparator B. Inverter C. Adder D. Comparator

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