Electronics :: All Aptitude Test ::

1.Convert (214)8 into decimal?
A. (140)10
B. (141)10
C. (142)10
D. (140)10

2.Convert (0.345)10 into an octal number?
A. (0.16050)8
B. (0.26050)8
C. (0.19450)8
D. (0.16050)8

3.Convert the binary number (01011.1011)2 into decimal?
A. (11.6875)10
B. (11.5874)10
C. (10.9876)10
D. (11.6875)10

4.Octal to binary conversion: (24)8 =?
A. (111101)2
B. (010100)2
C. (111100)2
D. (111101)2

5.Convert binary to octal: (110110001010)2 =?
A. (5512)8
B. (6612)8
C. (4532)8
D. (5512)8

6.What is the addition of the binary numbers 11011011010 and 010100101?
A. 0111001000
B. 1100110110
C. 11101111111
D. 0111001000

7.Perform binary addition: 101101 + 011011 = ?
A. 011010
B. 1010100
C. 101110
D. 011010

8.Perform binary subtraction: 101111 – 010101 = ?
A. 100100
B. 010101
C. 011010
D. 100100

9.Binary subtraction of 100101 – 011110 is?
A. 000111
B. 111000
C. 010101
D. 000111

10.Perform multiplication of the binary numbers: 01001 × 01011 = ?
A. 001100011
B. 110011100
C. 010100110
D. 001100011

11.100101 × 0110 = ?
A. 1011001111
B. 0100110011
C. 101111110
D. 1011001111

12.On multiplication of (10.10) and (01.01), we get?
A. 101.0010
B. 0010.101
C. 011.0010
D. 101.0010

13.Divide the binary numbers: 111101 ÷ 1001 and find the remainder?
A. 0010
B. 1010
C. 1100
D. 0010

14.Divide the binary number (011010000) by (0101) and find the quotient?
A. 100011
B. 101001
C. 110010
D. 100011

15.Binary subtraction of 101101 – 001011 = ?
A. 100010
B. 010110
C. 110101
D. 100010

16.1’s complement of 1011101 is?
A. 0101110
B. 1001101
C. 0100010
D. 0101110

17.2’s complement of 11001011 is?
A. 01010111
B. 11010100
C. 00110101
D. 01010111

18.On subtracting (01010)2 from (11110)2 using 1’s complement, we get?
A. 01001
B. 11010
C. 10101
D. 01001

19.On subtracting (010110)2 from (1011001)2 using 2’s complement, we get?
A. 0111001
B. 1100101
C. 0110110
D. 0111001

20.On subtracting (001100)2 from (101001)2 using 2’s complement, we get?
A. 1101100
B. 011101
C. 11010101
D. 1101100

21.On addition of 28 and 18 using 2’s complement, we get ?
A. 00101110
B. 0101110
C. 00101111
D. 00101110

22.On addition of +38 and -20 using 2’s complement, we get?
A. 11110001
B. 100001110
C. 010010
D. 11110001

23.On addition of -46 and +28 using 2’s complement, we get?
A. -10010
B. -00101
C. 01011
D. -10010

24.On addition of -33 and -40 using 2’s complement, we get?
A. 1001110
B. -110101
C. 0110001
D. 1001110

25.On subtracting +28 from +29 using 2’s complement, we get?
A. 11111010
B. 111111001
C. 100001
D. 11111010

26.If the number of bits in the sum exceeds the number of bits in each added numbers, it results in?
A. Successor
B. Overflow
C. Underflow
D. Successor

27.An overflow is a?
A. Hardware problem
B. Software problem
C. User input problem
D. Hardware problem

28.An overflow occurs in?
A. MSD position
B. LSD position
C. Middle position
D. MSD position

29.Logic circuitry is used to detect?
A. Underflow
B. MSD
C. Overflow
D. Underflow

30.1’s complement can be easily obtained by using?
A. Comparator
B. Inverter
C. Adder
D. Comparator


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