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Home » Technical » Aptitude Test - 8
Hassan
1.Convert (0.345)10 into an octal number?
A. (0.16050)8
B. (0.26050)8
C. (0.19450)8
D. (0.16050)8
2.Convert the binary number (01011.1011)2 into decimal?
A. (11.6875)10
B. (11.5874)10
C. (10.9876)10
D. (11.6875)10
3.Octal to binary conversion: (24)8 =?
A. (111101)2
B. (010100)2
C. (111100)2
D. (111101)2
4.Convert binary to octal: (110110001010)2 =?
A. (5512)8
B. (6612)8
C. (4532)8
D. (5512)8
5.What is the addition of the binary numbers 11011011010 and 010100101?
A. 0111001000
B. 1100110110
C. 11101111111
D. 0111001000
6.Perform binary addition: 101101 + 011011 = ?
A. 011010
B. 1010100
C. 101110
D. 011010
7.Perform binary subtraction: 101111 – 010101 = ?
A. 100100
B. 010101
C. 011010
D. 100100
8.Binary subtraction of 100101 – 011110 is?
A. 000111
B. 111000
C. 010101
D. 000111
9.Perform multiplication of the binary numbers: 01001 × 01011 = ?
A. 001100011
B. 110011100
C. 010100110
D. 001100011
10.100101 × 0110 = ?
A. 1011001111
B. 0100110011
C. 101111110
D. 1011001111
11.On multiplication of (10.10) and (01.01), we get?
A. 101.0010
B. 0010.101
C. 011.0010
D. 101.0010
12.Divide the binary numbers: 111101 ÷ 1001 and find the remainder?
A. 0010
B. 1010
C. 1100
D. 0010
13.Divide the binary number (011010000) by (0101) and find the quotient?
A. 100011
B. 101001
C. 110010
D. 100011
14.Binary subtraction of 101101 – 001011 = ?
A. 100010
B. 010110
C. 110101
D. 100010
15.1’s complement of 1011101 is?
A. 0101110
B. 1001101
C. 0100010
D. 0101110
16.2’s complement of 11001011 is?
A. 01010111
B. 11010100
C. 00110101
D. 01010111
17.On subtracting (01010)2 from (11110)2 using 1’s complement, we get?
A. 01001
B. 11010
C. 10101
D. 01001
18.On subtracting (010110)2 from (1011001)2 using 2’s complement, we get?
A. 0111001
B. 1100101
C. 0110110
D. 0111001
19.On subtracting (001100)2 from (101001)2 using 2’s complement, we get?
A. 1101100
B. 011101
C. 11010101
D. 1101100
20.On addition of 28 and 18 using 2’s complement, we get ?
A. 00101110
B. 0101110
C. 00101111
D. 00101110
21.On addition of +38 and -20 using 2’s complement, we get?
A. 11110001
B. 100001110
C. 010010
D. 11110001
22.On addition of -46 and +28 using 2’s complement, we get?
A. -10010
B. -00101
C. 01011
D. -10010
23.On addition of -33 and -40 using 2’s complement, we get?
A. 1001110
B. -110101
C. 0110001
D. 1001110
24.On subtracting +28 from +29 using 2’s complement, we get?
A. 11111010
B. 111111001
C. 100001
D. 11111010
25.If the number of bits in the sum exceeds the number of bits in each added numbers, it results in?
A. Successor
B. Overflow
C. Underflow
D. Successor
26.An overflow is a?
A. Hardware problem
B. Software problem
C. User input problem
D. Hardware problem
27.An overflow occurs in?
A. MSD position
B. LSD position
C. Middle position
D. MSD position
28.Logic circuitry is used to detect?
A. Underflow
B. MSD
C. Overflow
D. Underflow
29.1’s complement can be easily obtained by using?
A. Comparator
B. Inverter
C. Adder
D. Comparator
30.The advantage of 2’s complement system is that?
A. Only one arithmetic operation is required
B. Two arithmetic operations are required
C. No arithmetic operations are required
D. Only one arithmetic operation is required
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