Latent Heat :: Discussion


4.50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture?
A.0°C
B.40°C
C.60°C
D.4°C
Answer:  Option  A
Explanation:

Heat required to melt 50g ice = mL = 50×80=4000cal
Heat given out by water in cooling from 80°C to 0 = mc∆T=50×1×80=4000cal
Heat given by water is just sufficient to melt the whole ice. So the final temperature is 0°C.

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Published by:Michael Daani

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