Weight of a Body :: Discussion


4.The escape velocity in earth is 11.2km/s. What will be its value on a planet whose radius is double the radius of the earth and eight times the mass of the earth?
A.22.2km/s
B.22.4km/s
C.12km/s
D.24.2km/s
Answer:  Option  B
Explanation:

vp/ve =√((2GMp)/Rp)×√(Rg/(2GMe )) = √(Mp/Me ×Re/Rp)
vp/ve = √(8×1/2)=2
vp=2ve=2×11.2=22.4km/s.

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Published by:Michael Daani

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