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Motion in a Plane :: Discussion
| 9. | Find the magnitude of the centripetal acceleration of a particle on the tip of a fan blade, 0.30 metre in diameter, rotation at 1200 rev/minute? | |
| A. | 40 m/s2 | |
| B. | 4737.6 m/s2 | |
| C. | 245 m/s2 | |
| D. | 20 m/s2 | |
| Answer: Option B | |
| Explanation: | |
|
v = 1200/60 = 20rps ω = 2πv = 2×π×20 = 40π rad/sec Magnitude of acceleration = rω2 = 0.30×(40π)2 = 4737.6 m/s2 . |
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