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Numbers-Data Intensity 1 :: Discussion
| 28. | If n is a natural number, then (6n2 + 6n) is always divisible by? | |
| A. | 6 only | |
| B. | 6 and 12 both | |
| C. | 12 only | |
| D. | by 18 only | |
| Answer: Option B | |
| Explanation: | |
|
(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even. |
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