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Acceleration due to Gravity :: Discussion

6.	A bullet fired into a fixed target loss half of its velocity after penetrating 3cm. How much further will it penetrate before coming to rest assuming that it faces constant resistance in motion?
	A.	2cm
	B.	3cm
	C.	1cm
	D.	1.5cm

	Answer: Option C


	Explanation:
	If u is initial velocity then v=u/2 s=3cm As v2 -u2=2as a = -u2 /8 Now v=0 Initial velocity=u/2 s=1cm Thus the bullet will penetrate a further distance of 1cm before coming to rest



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Published by:Michael Daani

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