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H.C.F and L.C.M Problems-Data Intensity 1 :: Discussion
| 1. | Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. | |
| A. | 4 | |
| B. | 7 | |
| C. | 9 | |
| D. | 11 | |
| Answer: Option A | |
| Explanation: | |
|
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4. |
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