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Numbers-Data Intensity 2 :: Discussion

36.	(1² + 2² + 3² + ... + 10²) = ?
	A.	330
	B.	345
	C.	365
	D.	385

Answer: Option D

Explanation:

We know that (1² + 2² + 3² + ... + n²) = 1 n(n + 1)(2n + 1)

6

Putting n = 10, required sum = 1 x 10 x 11 x 21 = 385

6

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Published by:Michael Daani

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