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Numbers-Data Intensity 3 :: Discussion
| 15. | The smallest 5 digit number exactly divisible by 41 is? | |
| A. | 1004 | |
| B. | 10004 | |
| C. | 10045 | |
| D. | 10025 | |
| Answer: Option B | |
| Explanation: | |
The smallest 5-digit number = 10000.
41) 10000 (243
82
---
180
164
----
160
123
---
37
---
Required number = 10000 + (41 - 37)
= 10004. |
|
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