Height and Distance - General Questions Questions and Answers Discussion Page.

4.	An observer 1.6 m tall is 20 √ 3 away from a tower. The angle of elevation from his eye to the top of the tower is 30Â°. The height of the tower is?
	A.	21.6 m
	B.	23.2 m
	C.	24.72 m
	D.	None of Above

Answer: Option A

Explanation:

Let AB be the observer and CD be the tower.

Draw BE CD.

Then, CE = AB = 1.6 m,

BE = AC = 20√3 m.

DE	= tan 30° =	1
BE	= tan 30° =	√3

DE =	20√3	m = 20 m.
	√3

CD = CE + DE = (1.6 + 20) m = 21.6 m.

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Published by:Michael Daani

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