Transverse Waves :: Discussion


5.A whistle giving out 450Hz approaches a stationary observer at a speed of 33m/s. The frequency heard by the observer in Hz is (speed of sound = 330m/s).
A.409
B.429
C.517
D.500
Answer:  Option  D
Explanation:

v=v/(v-vs)×v
v=330/(330-33)×450=500Hz.

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Published by:Michael Daani

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