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26. | On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is? | |
A. | 10 | |
B. | 11 | |
C. | 12 | |
D. | 13 | |
Answer: Option A | |
Explanation: | |
Clearly, (2272 - 875) = 1397, is exactly divisible by N. Now, 1397 = 11 x 127 The required 3-digit number is 127, the sum of whose digits is 10. |
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