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Harmonic Motion :: Discussion
| 3. | What is the maximum acceleration of the particle executing the simple harmonic motion, y = 2sin[(πt/2)+φ], where y is in cm? | |
| A. | π/2 cm/s2 | |
| B. | π2/2 cm/s2 | |
| C. | π/4 cm/s2 | |
| D. | π2/4 cm/s2 | |
| Answer: Option B | |
| Explanation: | |
|
y=2sin[(πt/2)+] y=Asin(ωt+φ) |
|
| Tutorial Link: |
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