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Periodic Motion :: Discussion
| 11. | A spring 40mm long is stretched by the acceleration of a force. If 10N force is required to stretch the spring through 1mm, then work done in stretching through 40mm is? | |
| A. | 84J | |
| B. | 48J | |
| C. | 24J | |
| D. | 8J | |
| Answer: Option D | |
| Explanation: | |
|
k=F/x=10N/1mm=10N/(10-3m)=(104)N/m |
|
| Tutorial Link: |
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