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Chapter-1 - 11th - Basic Concepts Preparation :: Discussion

47.	How many atoms of carbon are present in 18 g of glucose C₆H₁₂O₆:
	A.	6.02 x 10²²
	B.	3.6 x 10²³
	C.	6.0 x 10²³
	D.	3.6 x 10²⁴

	Answer: Option B


	Explanation:




	Tutorial Link:

Published by:Michael Daani

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