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15. | The smallest 5 digit number exactly divisible by 41 is? | |
A. | 1004 | |
B. | 10004 | |
C. | 10045 | |
D. | 10025 | |
Answer: Option B | |
Explanation: | |
The smallest 5-digit number = 10000. 41) 10000 (243 82 --- 180 164 ---- 160 123 --- 37 --- Required number = 10000 + (41 - 37) = 10004. |
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