M = 25kg, R = 0.2m, α = 2rad/s²
Moment of inertia of the flywheel about its axis,
I = 1/2 MR²=1/2×25×0.2²=0.5kgm²
As torque, τ = F×R=I×α
Therefore, Force F = Iα/R=(0.5×2)/0.2=5N.