Angular Momentum :: Discussion


2.A hook of radius 2m weighs 100kg. It rolls along a horizontal floor so that its centre if mass has a speed of 20cm/s. How much work has to be done to stop it?
A.5 J
B.6 J
C.2 J
D.4 J
Answer:  Option  D
Explanation:

vcm=20cm/s = 0.20ms
Work required to stop the hoop = Rotational kinetic energy+Traslational kinetic energy
Work required = 1/2Iω2+1/2Mv2cm=4J.

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Published by:Michael Daani

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