Einstein’s Special Theory of Relativity :: Discussion


6.A man, who weighs 60 kg on earth, weighs 61 kg on a rocket, as measured by an observer on earth. What is the speed of the rocket?
A.2.5 X 108 m/s
B.2.5 X 107 m/s
C.5.5 X 107 m/s
D.5.5 X 108 m/s
Answer:  Option  C
Explanation:

Now, as we know m = m01V2c2
Here, m = 61 kg and m0 = 60 kg
Therefore, 61/60 = 1/1V2c2−−−−−−√
v2/c2 = 1 – (60/61)2 = 121/3600
v = 11 X c/60 = 5.5 X 107 m/s.

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Published by:Michael Daani

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