Wave Motion :: Discussion


9.A particle executes simple harmonic motion, its time period is 16s. If it passes through the centre of oscillation, then its velocity is 2 m/s at time 2s. The amplitude will be?
A.7.2m
B.4cm
C.6cm
D.0.72m
Answer:  Option  A
Explanation:

 Here,
t=2s,v=2m/s,T=16s
v=Aωcosωt
2=A×2π/14×cos⁡(2π/16×2)
A=(16√2)/π=7.2m.

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Published by:Michael Daani

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