H.C.F and L.C.M Problems-Data Intensity 1 Multiple Questions and Answers.
Exercise Questions ::
H.C.F and L.C.M Problems
Answer: Option A
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
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Answer: Option C
Explanation:
Clearly, the numbers are (23 x 13) and (23 x 14).
Hence: Larger number = (23 x 14) = 322.
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3. Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
A. 4 B. 10 C. 15 D. 16
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Answer: Option D
Explanation:
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes, they will toll together
30
+ 1 = 16 times.
2
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4. Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is?
A. 4 B. 5 C. 6 D. 8
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Answer: Option A
Explanation:
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
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Answer: Option C
Explanation:
Greatest number of 4-digits is 9999.
L.C.M. of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399.
Hence: Required number (9999 - 399) = 9600.
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