The extension in a string, obeying Hooke’s law, is x. The speed of sound in the stretched string is v. If the extension in the spring is increased to 1.5x, the speed of sound will be?
A.
1.22v
B.
0.16v
C.
1.50v
D.
0.75v
Answer: Option A
Explanation:
According to Hooke’s law, Tension (T) is proportional to Extension (x) Also, speed of sound, v∝√T v‘∝√1.5x v‘/v=√1.5=1.22 v‘=1.22v.
A wave represented by the equation y=acos(kx-ωt) is superposed with another wave to form a stationary wave such that point x=0 is a node. The equation for the other wave is?
A.
acos(kx-ωt)
B.
-acos(kx-ωt)
C.
-acos(kx+ωt)
D.
-asin(kx-ωt)
Answer: Option C
Explanation:
For the formation of a stationary wave, two identical waves travelling in opposite directions must separate each other. At x=0, resultant y should be zero for getting a node. Hence -acos(kx+ωt) is the correct answer.
A whistle giving out 450Hz approaches a stationary observer at a speed of 33m/s. The frequency heard by the observer in Hz is (speed of sound = 330m/s).