#include<stdio.h>int main()
{
int a=10;
void f();
a = f();
printf("%d\n", a);
return0;
}
void f()
{
printf("Hi");
}
A.
Error: Not allowed assignment
B.
Error: Doesn't print anything
C.
No error
D.
None of above
Answer: Option A
Explanation:
The function void f() is not visible to the compiler while going through main() function. So we have to declare this prototype void f(); before to main() function. This kind of error will not occur in modern compilers.
