Control Instructions - Point Out Errors Multiple Questions and Answers.
Exercise Questions ::
Control Instructions
1. Point out the error, if any in the for loop.
#include<stdio.h>
int main()
{
int i=1 ;
for (;;)
{
printf("%d\n" , i++);
if (i>10 )
break ;
}
return 0 ;
}
A. There should be a condition in the for loop B. The two semicolons should be dropped C. The for loop should be replaced with while loop. D. No error
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Answer: Option D
Explanation:
Step 1 : for(;; ) this statement will genereate infinite loop.Step 2 : printf("%d\n", i++); this statement will print the value of variable i and increement i by 1(one).Step 3 : if(i>10) here, if the variable i value is greater than 10, then the for loop breaks.
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Published by:Michael Daani
2. Point out the error, if any in the program?
#include<stdio.h>
int main()
{
int a = 10 ;
switch (a)
{
}
printf("This is c program." );
return 0 ;
}
A. Error: No case statement specified B. Error: No default specified C. No Error D. Error: infinite loop occurs
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Answer: Option C
Explanation:
There can exists a switch statement, which has no case .
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3. Point out the error, if any in the program.
#include<stdio.h>
int main()
{
int i = 1 ;
switch (i)
{
printf("This is c program." );
case 1 :
printf("Case1" );
break ;
case 2 :
printf("Case2" );
break ;
}
return 0 ;
}
A. Error: No default specified B. No Error and prints "Case1" C. Error: Invalid printf statement after switch statement D. None of above
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Answer: Option B
Explanation:
switch(i) becomes switch(1) , then the case 1: block is get executed. Hence it prints "Case1".
printf("This is c program."); is ignored by the compiler.
Hence there is no error and prints "Case1".
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Published by:Michael Daani
4. Point out the error, if any in the while loop?
#include<stdio.h>
int main()
{
int i=1 ;
while ()
{
printf("%d\n" , i++);
if (i>10 )
break ;
}
return 0 ;
}
A. There should be a condition in the while loop B. There should be at least a semicolon in the while C. The while loop should be replaced with for loop. D. Error
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Answer: Option A
Explanation:
The while() loop must have conditional expression or it shows "Expression syntax" error.
Example : while(i > 10){ ... }
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5. Which of the following errors would be reported by the compiler on compiling the program given below?
#include<stdio.h>
int main()
{
int a = 5 ;
switch (a)
{
case 1 :
printf("First" );
case 2 :
printf("Second" );
case 3 + 2 :
printf("Third" );
case 5 :
printf("Final" );
break ;
}
return 0 ;
}
A. There is no break statement in each case. B. Expression as in case 3 + 2 is not allowed. C. Duplicate case case 5: D. None of above
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Answer: Option C
Explanation:
Because, case 3 + 2: and case 5: have the same constant value 5.
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