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ENTRANCE TEST – 2010 Multiple Questions and Answers.
| 26. | If length of a spanner is ‘I’ and a force ‘F’ is applied on it to tighten a nut such that it passes through the pivot point, then torque is | ||
| A. | Zero | ||
| B. | Ff | ||
| C. | Fl sin θ | ||
| D. | Fl sin θλ | ||
| 27. | If a force of magnitude 8 N acts on a body in direction making an angle 30, its x and y components will be | ||
| A. | Fx = 4√3 and Fy = 8 | ||
| B. | Fx = 8 and Fy = 4√3 | ||
| C. | Fx = 4√3 and Fy = 4 | ||
| D. | Fx = 8√3 and Fy = 4 | ||
| 28. | The difference of a vector B⃗ and its negative vector – ⃗ is | ||
| A. | A null vector | ||
| B. | Equal to magnitude of vector B⃗ | ||
| C. | Twice the magnitude of vector B⃗ | ||
| D. | Smaller than magnitude of vector B⃗ | ||
| 29. | If the velocity of the body changes by equal amount in equal intervals of time, the body is said to have: | ||
| A. | variable acceleration | ||
| B. | uniform acceleration | ||
| C. | uniform velocity | ||
| D. | negative acceleration | ||
| 30. | In order to determine the maximum height of the projectile, the equation of motion used is | ||
| A. | aS = vf 2 - vi̇ 2 | ||
| B. | 2aS = vf 2 - vi̇ | ||
| C. | 2S = a vf 2 - vi̇ 2 | ||
| D. | aS = 2 vf 2 - vi ̇ 2 | ||
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