Numbers-Data Intensity 1 Multiple Questions and Answers.
Exercise Questions ::
Numbers
| Answer: Option C |
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Let the required fraction be x. Then |
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- x = |
9 |
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20 |
20 - 20x2 = 9x
20x2 + 9x - 20 = 0
20x2 + 25x - 16x - 20 = 0
5x(4x + 5) - 4(4x + 5) = 0
(4x + 5)(5x - 4) = 0
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Published by:Michael Daani
| Answer: Option B |
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| Explanation: |
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Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R. |
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Published by:Michael Daani
| Answer: Option B |
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| Explanation: |
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(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even. |
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Published by:Michael Daani
| Answer: Option C |
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| Explanation: |
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107 x 107 + 93 x 93 |
= (107)2 + (93)2 |
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= (100 + 7)2 + (100 - 7)2 |
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= 2 x [(100)2 + 72] [Ref: (a + b)2 + (a - b)2 = 2(a2 + b2)] |
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= 20098 |
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Published by:Michael Daani
| Answer: Option C |
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| Explanation: |
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(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder. |
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Tutorial Link: |
Published by:Michael Daani
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