A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by T=2π√(l/g), where g is equal to?
A.
g
B.
g-a
C.
g+a
D.
√(g2+a2 )
Answer: Option D
Explanation:
As g and a are acting along perpendicular directions, the effective value of acceleration due to gravity is g‘=√(g2+a2).
The composition of two simple harmonic motions of equal periods at the right angle to each other and with a phase difference of π results in the displacement of the particle along?
A.
Circle
B.
Figure of eight
C.
Straight line
D.
Ellipse
Answer: Option C
Explanation:
Let x = asinωt y=bsin(ωt+π)=-bsinωt x/a=y/b y=-b/a×x This is the equation of a straight line.
A particle executes simple harmonic motion, its time period is 16s. If it passes through the centre of oscillation, then its velocity is 2 m/s at time 2s. The amplitude will be?
A body is executing the simple harmonic motion with an angular frequency of 2rad/sec. Velocity of the body at 20m displacement, when amplitude of motion is 60m, is?
