At the equator, g_e=g-Rω²
When ω=0, g_e=g
The value of g increases if the earth stops rotating.

Near the earth’s surface,
v₀=√gR=7.2km/s
Approximately 8km/s.

Near earth’s surface,
v₀=v_e/√2=2/√2=√2 km/s.

The central gravitational force decreases which does not exert any torque. Hence the angular momentum and consequently areal velocity remain unchanged.

The escape velocity v_e=√2gR, does not depend upon the mass of the projected body. Thus we need the same velocity to project an elephant and an ant into space.