Floating Point Issues - Find Output of Program Multiple Questions and Answers.
Exercise Questions ::
Floating Point Issues
1. What will be the output of the program?
#include<stdio.h>
int main()
{
float a=0.7 ;
if (a < 0.7 )
printf("C\n" );
else
printf("C++\n" );
return 0 ;
} A. C++ B. C C. Compiler error D. None of above
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Answer: Option B
Explanation:
if(a < 0.7) here a is a float variable and 0.7 is a double constant. The float variable a is less than double constant 0.7 . Hence the if condition is satisfied and it prints 'C'
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Published by:Michael Daani
2. What will be the output of the program?
#include<stdio.h>
int main()
{
float *p;
printf("%d\n" , sizeof (p));
return 0 ;
} A. 2 in 16bit compiler, 4 in 32bit compiler B. 4 in 16bit compiler, 2 in 32bit compiler C. 4 in 16bit compiler, 4 in 32bit compiler D. 2 in 16bit compiler, 2 in 32bit compiler
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Answer: Option A
Explanation:
sizeof(x) x float *p float
In 16 bit compiler, the pointer size is always 2 bytes.
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Published by:Michael Daani
Answer: Option D
Explanation:
printf("%d\n", (int)fval); (int)fval
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4. What will be the output of the program?
#include<stdio.h>
#include<math.h>
int main()
{
printf("%f\n" , sqrt(36.0 ));
return 0 ;
} A. 6.0 B. 6 C. 6.000000 D. Error: Prototype sqrt() not found.
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Answer: Option C
Explanation:
printf("%f\n", sqrt(36.0));
Declaration Syntax : double sqrt(double x)
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Published by:Michael Daani
5. What will be the output of the program?
#include<stdio.h>
#include<math.h>
int main()
{
printf("%d, %d, %d\n" , sizeof (3.14 f), sizeof (3.14 ), sizeof (3.14 l));
return 0 ;
} A. 4, 4, 4 B. 4, 8, 8 C. 4, 8, 10 D. 4, 8, 12
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Answer: Option C
Explanation:
sizeof(3.14f) float
sizeof(3.14) double
sizeof(3.14l) long double
Note: If you run the above program in Linux platform (GCC Compiler) it will give 4, 8, 12 as output. If you run in Windows platform (TurboC Compiler) it will give 4, 8, 10 as output. Because, C is a machine dependent language.
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Published by:Michael Daani
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