A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be?
A.
1, 2
B.
2, 3
C.
3, 2
D.
4, 1
Answer: Option B
Explanation:
4 | xy = (5 x 1 + 4) = 9
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5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37
--------
| 1 -4
Now, 37 when divided successively by 5 and 4, we get
5 | 37
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4 | 7 - 2
---------
| 1 - 3
Respective remainders are 2 and 3.