A man, who weighs 60 kg on earth, weighs 61 kg on a rocket, as measured by an observer on earth. What is the speed of the rocket?
A.
2.5 X 108 m/s
B.
2.5 X 107 m/s
C.
5.5 X 107 m/s
D.
5.5 X 108 m/s
Answer: Option C
Explanation:
Now, as we know m = m01−V2c2√ Here, m = 61 kg and m0 = 60 kg Therefore, 61/60 = 1/1−V2c2−−−−−−√ v2/c2 = 1 – (60/61)2 = 121/3600 v = 11 X c/60 = 5.5 X 107 m/s.