The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increases length is?
A.
50%
B.
21%
C.
30%
D.
10.5%
Answer: Option D
Explanation:
Time period, T=2π√(l/g) The percentage increase in a time period is given by, ∆T/T×100=1/2×∆l/l×100 ∆T/T×100=1/2×21%=10.5%.
A spring of spring constant 5×103N/m is stretched initially by 5cm from the unstretched position. Then the work done to stretch is further by another 5cm is?
A particle executes simple harmonic motion with an angular velocity of 3.5 rad/sec and maximum velocity acceleration 7.5 m/s2 respectively. What is the amplitude of oscillations?