#include<stdio.h>int sumdig(int);
int main()
{
int a, b;
a = sumdig(123);
b = sumdig(123);
printf("%d, %d\n", a, b);
return 0;
}
int sumdig(int n)
{
int s, d;
if(n!=0)
{
d = n%10;
n = n/10;
s = d+sumdig(n);
}
else
return 0;
return s;
}
#include<stdio.h>int main()
{
int fun(int);
int i = fun(10);
printf("%d\n", --i);
return 0;
}
int fun(int i)
{
return (i++);
}
A.
8
B.
9
C.
10
D.
11
Answer: Option B
Explanation:
Step 1: int fun(int); Here we declare the prototype of the function fun().
Step 2: int i = fun(10); The variable i is declared as an integer type and the result of the fun(10) will be stored in the variable i.
Step 3: int fun(int i){ return (i++); } Inside the fun() we are returning a value return(i++). It returns 10. because i++ is the post-increement operator.
Step 4: Then the control back to the main function and the value 10 is assigned to variable i.
Step 5: printf("%d\n", --i); Here --i denoted pre-increement. Hence it prints the value 9.
#include<stdio.h>int check (int, int);
int main()
{
int c;
c = check(10, 20);
printf("c=%d\n", c);
return 0;
}
int check(int i, int j)
{
int *p, *q;
p=&i;
q=&j;
i>=45 ? return(*p): return(*q);
}
A.
Print 10
B.
Print 20
C.
Print 1
D.
Compile error
Answer: Option D
Explanation:
There is an error in this linei>=45 ? return(*p): return(*q);. We cannot use returnkeyword in the terenary operators.
#include<stdio.h>int fun(int, int);
typedef int (*pf) (int, int);
int proc(pf, int, int);
int main()
{
printf("%d\n", proc(fun, 6, 6));
return 0;
}
int fun(int a, int b)
{
return (a==b);
}
int proc(pf p, int a, int b)
{
return ((*p)(a, b));
}
