Kepler’s second law states that the radius vector drawn from the sun to a planet, sweeps out equal areas in equal intervals of time. It is based on the law of conservation of angular momentum.
For a satellite escape velocity from the earth is 11.2 km/s. If a body is to be projected in a direction making an angle 45° to the vertical, then what is the escape velocity?
A.
11.2×2km/s
B.
11.2km/s
C.
11.2×√2km/s
D.
11.2/√2km/s
Answer: Option B
Explanation:
Escape velocity does not depend on the angle of the projection of the body from the earth’s surface. Therefore v = 11.2 km/s.