1. | A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is? |
| |
| A. | 160.2 C |
| B. | -160.2 C |
| C. | 16.02 C |
| D. | -16.02 C |
|
|
| Answer: Option C |
|
|
| Explanation: |
|
n 1020, Q = ne = e 1020 = 16.02 C. Charge on sphere will be positive. |
| See More Information |
|
|
|
Tutorial Link: |
Published by:
2. | A lightning bolt carrying 15,000 A lasts for 100 s. If the lightning strikes an airplane flying at 2 km, the charge deposited on the plane is? |
| |
| A. | 13.33 C |
| B. | 75 C |
| C. | 1500 C |
| D. | 1.5 C |
|
|
3. | If 120 C of charge passes through an electric conductor in 60 sec, the current in the conductor is ? |
| |
| A. | 0.5 A |
| B. | 2 A |
| C. | 3.33 mA |
| D. | 0.3 mA |
|
|
4. | The energy required to move 120 coulomb through 3 V is? |
| |
| A. | 25 mJ |
| B. | 360 J |
| C. | 40 J |
| D. | 2.78 mJ |
|
|
5. | Consider the circuit graph shown in figure below. Each branch of circuit graph represent a circuit element. The value of voltage V1 is? |
| 
|
| A. | 30 V |
| B. | 25 V |
| C. | 20 V |
| D. | 15 V |
|
|
| Answer: Option D |
|
|
| Explanation: |
|
100 = 65 + V2 => V2 = 35 V V3 – 30 = V2 => V3 = 65 V 105 – V3 + V4 – 65 = 0 => V4 = 25 V V4 + 15 – 55 + V1 = 0 => V1 = 15 V. |
| See More Information |
|
|
|
Tutorial Link: |
Published by:
Read More..
Online Test : Take an Online Basic Electronics Aptitude Test Now!