Speed =		60 x	5	m/sec	=		50	m/sec.
			18				3

Length of the train = (Speed x Time).

Length of the train =		50	x 9	m = 150 m.
		3

Speed of the train relative to man =		125	m/sec
		10

=		25	m/sec.
		2

=		25	x	18	km/hr
		2		5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

 x - 5 = 45          x = 50 km/hr.

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

	27x + 17y	= 23
	x+ y

 27x + 17y = 23x + 23y

 4x = 6y

	x	=	3	.
	y		2

Speed =		45 x	5	m/sec	=		25	m/sec.
			18				2

Time = 30 sec.

Let the length of bridge be x metres.

 2(130 + x) = 750

 x = 245 m.

Speed =		54 x	5	m/sec = 15 m/sec.
			18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

 x + 300 = 540

 x = 240 m.